1.

Factorise a2b-25 (polynomial)​

Answer»

<P>Answer:

•Let (a−2b)=p, then the EQUATION 2(a−2b)

2

−25(a−2b)+12 becomes 2p

2

−25p+12

Consider the expression 2p

2

−25p+12 we can factorise it as follows:

2p

2

−25p+12=2p

2

−24p−p+12=2p(p−12)−1(p−12)=(2p−1)(p−12)

Now, SUBSTITUTE the VALUE of p as p=(a−2b):

(p−12)(2p−1)=(a−2b−12)(2(a−2b)−1)=(a−2b−12)(2a−4b−1)

Hence, 2(a−2b)

2

−25(a−2b)+12=(a−2b−12)(2a−4b−1).


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