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Factorise a square + b square minus 2 into a b minus AC + BC |
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Answer» = a^2 + b^2 - 2ab + 2ac - 2BC = (a- b)^2 + 2ac - 2bc [ we know that a^2 + b^2 - 2ab = (a-b)^2] = (a- b)^2 +2c (a-b) = (a- b) (a-b + 2c) Hope it HELPS.... |
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