Factorise:9a2 - 9b2 + 6a + 1 – InterviewSolution

1.	Factorise:9a2 - 9b2 + 6a + 1
Answer» \(9a^2 - 9b^2 + 6a + 1\) \(= 9a^2 + 6a + 1 - 9b^2\) \(= (3a + 1)^2 -(3b)^2 \) \((\because a^2 + 2ab + b^2 = (a + b)^2)\) \(= (3a + 1 - 3b)(3a + 1 + 3b)\) \((\because a^2 - b^2 = (a + b) (a - b))\) \(= (3 (a - b) + 1) (3(a + b) + 1)\)

Factorise:9a2 - 9b2 + 6a + 1

Answer»

\(9a^2 - 9b^2 + 6a + 1\)

\(= 9a^2 + 6a + 1 - 9b^2\)

\(= (3a + 1)^2 -(3b)^2 \) \((\because a^2 + 2ab + b^2 = (a + b)^2)\)

\(= (3a + 1 - 3b)(3a + 1 + 3b)\) \((\because a^2 - b^2 = (a + b) (a - b))\)

\(= (3 (a - b) + 1) (3(a + b) + 1)\)

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Factorise:9a2 - 9b2 + 6a + 1

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