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Factorise 9a square+4b square+16c square 12ab - 16bc-24ca |
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Answer» ONG>Step-by-step explanation: ANSWER 9a +4b 2 +16c 2 +2ab−16bc−24ca = (3A) 2 +(2b) 2 +(−4c) 2 +2(3a)(2b)+2(2b)(−4c)+2(−4c)(2a) Suitable identities is (x+y+z) 3 =x 3 +y 3 +z 3 +2xy+2yz+2xz Therefore, (3a) 2 +(2b) 2 +(−4c) 2 +2(3a)(2b)+2(2b)(−4c)+2(−4c)(2a) = (3a+2b−4c) 2 |
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