1.

Factorise 64m3+n3=? show me the best answer​

Answer»

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{64m}^{3} +  {n}^{3}  = ( {4})^{3} + ( {n})^{3}

{x}^{3} +  {y}^{3} = (x + y)( {x}^{2} - xy +  {y}^{2})

=  (4m + n)(( {4m})^{2} - 4m \times n + ({n})^{2})

= (4m + n)( {16m}^{2} - 4mn +  {n}^{2} )

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