Factorise ; 2x³ + y³ + 8z³ – 2√ xy + 4√ yz – 8xz

1.	Factorise ; 2x³ + y³ + 8z³ – 2√ xy + 4√ yz – 8xz
Answer» Answer: GIVEN 2X2 + Y2 + 8Z2 - 2√(2xy) + 4√(2yz) - 8xz = (-√2x)2 + y2 + {2√(2z)}2 - 2{(-√2x)y} + 2y{2√(2z)} + 2(-√2x){2√(2z)} = {-√2x + y + 2√(2z)}2 = {-√2x + y + 2√(2z)}*{-√2x + y + 2√(2z)} ANSWERED on: 2016/12/30 by ExamFear Share on Facebook Share of TwitterReport Abuse

Answer»

Answer:

GIVEN

2X2 + Y2 + 8Z2 - 2√(2xy) + 4√(2yz) - 8xz

= (-√2x)2 + y2 + {2√(2z)}2 - 2{(-√2x)*y} + 2y*{2√(2z)} + 2*(-√2x)*{2√(2z)}

= {-√2x + y + 2√(2z)}2

= {-√2x + y + 2√(2z)}*{-√2x + y + 2√(2z)}

ANSWERED on: 2016/12/30 by ExamFear Share on Facebook Share of TwitterReport Abuse

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Factorise ; 2x³ + y³ + 8z³ – 2√ xy + 4√ yz – 8xz

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