1.

Factorise 27 x ki power cube minus y ki power cube​

Answer»

27x^3-y^3=(3X)^3-y^3

a^3-b^3=(a-b)^3-3a^2b+3ab^2

(3x)^3-y^3=(3x-y)^3-3×9x^2y+3×3xy^2



Discussion

No Comment Found

Related InterviewSolutions