Factorise 216a³-2root2b³amd please don't write "I don't know"If you

1.	Factorise 216a³-2root2b³amd please don't write "I don't know"If you know then only answerplease
Answer» $Given \: 216a^{3} -2\sqrt{2} b^{3}$ $= 6^{3} a^{3} - (\sqrt{2})^{3} b^{3}$ $=( 6a)^{3} - (\sqrt{2}b)^{3}$ /* By ALGEBRAIC IDENTITY */ $\boxed{ \pink { x^{3} - y^{3} = (x-y)(x^{2}+xy+y^{2})}}$ $= (6a-\sqrt{2}b)[ (6a)^{2} + (6a)(\sqrt{2}b) + (\sqrt{2}b)^{2} ]$ $= (6a-\sqrt{2}b)(36a^{2} + 6\sqrt{2}ab + 2b^{2} )$ THEREFORE., $\red{ 216a^{3} -2\sqrt{2} b^{3} }$ $\green {= (6a-\sqrt{2}b)(36a^{2} + 6\sqrt{2}ab + 2b^{2} ) }$ •••♪