f5 times the jfifth term of an AP is equal to 8 times its eishone that

1.	f5 times the jfifth term of an AP is equal to 8 times its eishone that its 13th term is zero.
Answer» Let of the APfirst term= acommon difference=dATQ5[a+(5-1)d]=8[a+(8-1)d]5(a+4d)=8(a+7d)5a + 20d = 8a + 56d3a = 36da= -12dNow 13th terma+(13-1)d=-12d+12d=0(proved) Like my answer if you find it useful!

f5 times the jfifth term of an AP is equal to 8 times its eishone that its 13th term is zero.

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Let of the APfirst term= acommon difference=dATQ5[a+(5-1)d]=8[a+(8-1)d]5(a+4d)=8(a+7d)5a + 20d = 8a + 56d3a = 36da= -12dNow 13th terma+(13-1)d=-12d+12d=0(proved)

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f5 times the jfifth term of an AP is equal to 8 times its eishone that its 13th term is zero.

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