Saved Bookmarks
| 1. |
`f(x)={(x-1",",-1 le x le 0),(x^(2)",",0le x le 1):} and g(x)=sinx` Consider the functions `h_(1)(x)=f(|g(x)|) and h_(2)(x)=|f(g(x))|.` If for `h_(1)(x) and h_(2)(x)` are identical functions, then which of the following is not true?A. Domain of `h_(1)(x) and h_(2)(x)" is " x in [2n pi,(2n+1)pi],n in Z.`B. Range of `h_(1)(x) and h_(2)(x)" is " [0,1]`C. Period of `h_(1)(x) and h_(2)(x) " is " pi`D. None of these |
|
Answer» Correct Answer - C `|g(x)|=|sinx|, x in R` `f(|g(x)|)={(|sinx|-1",",-1 le |sinx| lt 0),((|sinx|)^(2)",", 0le (|sinx|) le 1):}=sin^(2)x,x in R` `f(g(x))={(sinx-1",",-1 le sinx lt 0),(sin^(2)x",", 0le sinx le 1):}` `={(sinx-1",",(2n-1) pi lt x lt 2n pi),(sin^(2)x",", 2n pi le x le (2n+1)pi):},n in Z.` or `|f(g(x))|={(sinx-1",",(2n-1) pi lt x lt 2n pi),(sin^(2)x",", 2n pi le x le (2n+1)pi):},n in Z.` For `h_(1)(x)-=h_(2)(x)=sin^(2)x, x in [2n pi,(2n+1) pi], n in Z,` and has range [0, 1] for the common domain. Also, the period is `2pi` (from the graph). |
|