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`f(x)=sin^(-1)[e^(x)]+sin^(-1)[e^(-x)]` where [.] greatest integer function thenA. domain of `f(x) " is " (-log_(e)2,log_(e)2)`B. range of `f(x) ={pi}`C. Range of `f(x) " is " {(pi)/(2),pi}`D. `f(x) =cos^(-1)x` has only one solution |
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Answer» Correct Answer - A::C We have `f(x)=sin^(-1)[e^(x)]+sin^(-1)[e^(-x)]` We must have `0 lt e^(x) lt 2 and 0 lt e^(-x) lt 2` `implies x in (-log_(e) 2, log_(e)2)` `implies f(x) ={(pi",",x=0),((pi)/(2)"," , x in (-log_(e)2","0)cup (0","log_(e)2)):}` |
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