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f(x)=9 \sin x+\sin 3 x, \text { find } f^{\prime}\left(\frac{\pi}{3}\right) |
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Answer» f(x) = 9sinx + sin3xf'(x) = 9cosx + 3 cos3xf'(pi/3) = 9 cos(pi/3) + 3 cos(3×pi/3)f'(pi/3) = 9 /2 - 3 = 3/2 |
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