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`f:R to R" given by "f(x)=x+sqrtx^(2)`,isA. injectiveB. surjectiveC. bijectiveD. none of these |
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Answer» Correct Answer - D We have `f(x)=x+sqrtx^(2)=x|x|={(,2x,xge0),(,x-x=0,xle0):}}` Clearly f is many-one into functions: |
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