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F 8. You are given several identical resistors eachof value 512 and each capable of carrying amaximum current of 2A. It is required to make asuitable combination of these resistances to producea resistance of 2.5, which can carry current of 4A.The minimum number of resistances required forthis job is1) 2. 2) 4 3) 6 4) 8 |
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Answer» nce of each resistor R=10Equivalent RESISTANCE of each segment R ′ =R+R=2R∴ R ′ =2×10=20Such 4 segments are connected in parallel to each other.Thus EQUIVALENT resistance of the circuit R p = 4R ′ ⟹ R p = 420 =5Maximum CURRENT flowing through each resistor is one ampere i.e. i=1AThus TOTAL current flowing through the circuit I=i+i+i+i∴ I=4i=4AThus minimum 8 resistors are required to satisfy the above conditions. |
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