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Express the trigonometric ratios sinA, secA and tanA in terms of cotA |
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Answer» Right answer [ i ] sinA in terms of cotA :sinA = 1 / cosecAWe know that: cosec²A = 1 + cot²AsinA = 1 / √1 + cot²A[ ii ] secA in terms of cotA :We know that: 1 + tan²A = sec²AsecA = 1 + tan²AsecA = 1 + 1 / cot²AsecA = √(cot²A + 1 ) /cotA[ iii ] tanA in terms of cotA :tanA = 1 / cotA |
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