Express the hcf of 210 and 55 as 210x+55y where x,y are integers

1.	Express the hcf of 210 and 55 as 210x+55y where x,y are integers
Answer» Answer:hi! here is your answer. 210 = 5 × 3 × 7×2 55 = 5 × 11 here... H.C.F = 5 H.C.F also can be expressed as 210x +55. 5 = 210x +55Y 210x + 55y = 5 [DIVIDING throughout by 5] 42X + 11Y = 1 hence expressed ! hope this helps !!# Step-by-step EXPLANATION:

Answer»

Answer:hi!

here is your answer.

210 = 5 × 3 × 7×2

55 = 5 × 11

here...

H.C.F = 5

H.C.F also can be expressed as 210x +55.

5 = 210x +55Y

210x + 55y = 5

[DIVIDING throughout by 5]

42X + 11Y = 1

hence expressed !

hope this helps !!#

Step-by-step EXPLANATION:

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Express the hcf of 210 and 55 as 210x+55y where x,y are integers

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