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Express in form of a+ib3(7+7i)+i(7+7i) |
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Answer» ONG>Answer: Given, 3(7+7i)+i(7+i7) =21+21i+7i+7i
=21+28i+7×(−1),[∵i 2 =−1] =14+28i=a+ib, where a=14,b=28 |
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