1.

Explain with process 2^x-7=5^x-4

Answer»
{2}^{x - 7}  =  {5}^{x - 4}  \\   apply \: log \: on \: both \: sides \\ (x - 7)log2 = (x - 4)log5 \\  \frac{(x - 7)}{(x - 4)}  = log(5 - 2) \\ x - 7 = xlog3 - 4log3 \\x(1 - log3) = 7 - 4log3 \\ x =  \frac{(7 -4 log3)}{(1 - log3)}  \\ x = 9.74


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