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Explain the variations of acceleration due to gravity inside and outside the earth and draw the graph. |
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Answer» SOLUTION :`implies`In `g(r) = 4/3 pi Grrho, 4/3 piGrho`Gp is CONSTANT . `:. g(r) prop r ` Means, the gravitational ACCELERATION (g) at a point inside the earth is directly proportional to the distance of that point from the centre of the earth. `implies` And `g(r) = (GM)/r^2` where `r gt gt R_E`so ,where `g(r) prop 1/r^2` where ` r gt gt R_E`. Hence starting from the centre of the earth g(r) increases in directly proportion as r increases and then OUTSIDE the surface g(r) decreases as inverse square of distance. `implies` The variations in gravitational acceleration with below the surface of earth and above the height from the surface is shown as in figure.
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