#(36.)u=0 a=1.8m/s^2S=10m v^2=u^2-2as v^2= 0-2×1.8×10 v^2=-16 v=-4 m/s #(37.) speed at 10 m(v1)= -4m/s speed at 20m(v2) = 0 Distance is directly proportional to the square of speed=> s= u^2 OPTION d is correct.#(38.)u= -4m/s v^2 = (-4)^2-2×1.8×10 v^2= 16-16 =0
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