Explain how E=P2/2m

1.	Explain how E=P2/2m
Answer» For a photon E=h.f (f=frequency) = hc/l (c=velocity of light) Hence E = p.c for photons. For non RELATIVISTIC bodies p = m.v and E = (1/2) m.v^2 so E = (p^2)/2m. This assumes m = REST MASS is independent of velocity. In general this is not TRUE if v^2/c^2 is not ~0 since m=m0/sqrt(1-v^2/c^2). So this formula is only valid at velocities at which relativistic EFFECTS can be ignored. *hope* *this* *helps*

Answer»

For a photon E=h.f (f=frequency) = hc/l (c=velocity of light)

Hence E = p.c for photons.

For non RELATIVISTIC bodies p = m.v and E = (1/2) m.v^2 so E = (p^2)/2m. This assumes m = REST MASS is independent of velocity. In general this is not TRUE if v^2/c^2 is not ~0 since m=m0/sqrt(1-v^2/c^2). So this formula is only valid at velocities at which relativistic EFFECTS can be ignored.

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Explain how E=P2/2m