EXERCISE S.1Prove that the function f(a) 5x-3 is continuous at x 0, at

1.	EXERCISE S.1Prove that the function f(a) 5x-3 is continuous at x 0, at x-3 and at x-5.1.
Answer» Given function isf(x) = 5x-3 Now at x = 0f(x) = 5(0) -3 => -3 limx→0 5(x)-3 = -3therefore limx→0 f(x) = f(0) hence function in continuous at x = 0 Now At x = -3 f(-3)= 5(-3)-3 = -18now lim x→-3 f(x) = 5(-3)-3= -18thus f(-3) = limx→-3 f(x)hence function Is continuous at x = -3 Now at x = 5f(x) = f(5) = 5(5)-3= 22also lim x→5 f(x) = lim x→5 5x-3= 5(5) - 3 => 22 Thus f(5) = lim x→5 f(x)hence function is continuous at x = 5

EXERCISE S.1Prove that the function f(a) 5x-3 is continuous at x 0, at x-3 and at x-5.1.

Answer»

Given function isf(x) = 5x-3

Now at x = 0f(x) = 5(0) -3 => -3

limx→0 5(x)-3 = -3therefore limx→0 f(x) = f(0) hence function in continuous at x = 0

Now At x = -3

f(-3)= 5(-3)-3 = -18now lim x→-3 f(x) = 5(-3)-3= -18thus f(-3) = limx→-3 f(x)hence function Is continuous at x = -3

Now at x = 5f(x) = f(5) = 5(5)-3= 22also lim x→5 f(x) = lim x→5 5x-3= 5(5) - 3 => 22

Thus f(5) = lim x→5 f(x)hence function is continuous at x = 5