EXERCISE 7B1. In the adjoining figure, AOB is a straightline. Find the

1.	EXERCISE 7B1. In the adjoining figure, AOB is a straightline. Find the value of x.
Answer» Step-by-step explanation: From the figure we KNOW that ∠AOB is a STRAIGHT line So we get ∠AOB = 180o It can also be written as ∠AOC + ∠COD + ∠BOD = 180o By SUBSTITUTING the VALUES (3x – 7) o + 55o + (x + 20) o = 180o 3x – 7o + 55o + x + 20o = 180o On further calculation 4X + 68o = 180o 4x = 112o By division x = 28o By substituting the value of x we get ∠AOC = (3x – 7)o = 3(28o) – 7o On further calculation = 84o – 7o By subtraction = 77o ∠BOD = (x + 20)o = (28 + 20)o By addition = 48oRead more on Sarthaks.com - https://www.sarthaks.com/716779/in-the-adjoining-figure-aob-is-a-straight-line-find-the-value-of-x-hence-find-aoc-and-bod

EXERCISE 7B1. In the adjoining figure, AOB is a straightline. Find the value of x.

Answer»

Step-by-step explanation:

From the figure we KNOW that ∠AOB is a STRAIGHT line So we get ∠AOB = 180o It can also be written as ∠AOC + ∠COD + ∠BOD = 180o By SUBSTITUTING the VALUES (3x – 7) o + 55o + (x + 20) o = 180o 3x – 7o + 55o + x + 20o = 180o On further calculation 4X + 68o = 180o 4x = 112o By division x = 28o By substituting the value of x we get ∠AOC = (3x – 7)o = 3(28o) – 7o On further calculation = 84o – 7o By subtraction = 77o ∠BOD = (x + 20)o = (28 + 20)o By addition = 48oRead more on Sarthaks.com - https://www.sarthaks.com/716779/in-the-adjoining-figure-aob-is-a-straight-line-find-the-value-of-x-hence-find-aoc-and-bod

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