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EXERCISE 12.3I. Find the area of the shaded region in Fig 12.19,irPO-24cm, PR 7 m and O is the centre of thecircke |
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Answer» AngleQPR=90 (Traingle formed in the semi circle is of 90°IN Traingle QPRBy pythagoras theorem H^2=P^2+B^2H^2=(7)^2+(24)^2H^2=49+576H^2=625H=√625H=25cmDiameter of circle =25cmRadius of circle= 25/2Area of Semi circle=pie(r)^2=1/2×22/7×25/2×25/2=245.5Area of traingle= 1/2×b×h=1/2×24×7= 12×7=84 Area of shaded region = Area of semicircle -Area of traingle=245.5-84=161.5 cm |
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