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EXERCISE 10.5. In Fig. 10.36, A.B and C are three points on acircle with centre Osuch that BOC 30° and<AOB 60°. If D is a point on the circle otherthan the arc ABC, find ZADCFig. 10.36 |
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Answer» ∠AOB = 60° ∠BOC= 30° Here,∠AOC = ∠AOB + ∠BOC ∠AOC = 60°+30° ∠AOC = 90° Since Arc ABC makes an angle of 90° at the centre of the circle. ∠ADC= 1/2∠AOC [SINCE THE ANGLE SUBTENDED BY AN ARC AT THE CENTRE IS DOUBLE THE ANGLE SUBTENDED BY IT AT ANY POINT ON THE REMAINING PART OF THE CIRCLE] ∠ADC= 1/2(90°) ∠ADC= 45° Hence, ∠ADC= 45° thanks sur ben thanks |
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