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EXERC1. Which of the following are quadratic equations?(i) x2 + 6x - 4 = 0(ii) 13x? - 2x + 1 = 0(ii) x + = 5(v) 2x2 - 3x + 9 = 0(vii) 3x? - 5x + 9 = x? - 7x + 3(vi) x2 - 2x - VX-5=0(vii) x++ = 1(ix) x2 - 3x = 0(xi) (2x + 1) (3x + 2) = 6(x - 1)(x - 2)(xii) x + 1 = x,x+0(xiv) (x + 2) = x3 - 4(xiii) 16x? - 3 = (2x + 5) (5x - 3)(xv) x(x + 1) + 8 = (x + 2)(x - 2) |
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Answer» any equation having highest power of x is 2 then that equation is called quadratic equation. and power must be positive.let's take an example:- (i) x2 + 6x - 4 = 0above equation has highest degree of the polynomial is 2 so it is a quadratic equation. https://youtu.be/wSMHWy_IQyAmore details study (2x+1)(3x+2)=6( x-1)(x-2); (6x^2+4x+3x+2)=6(x^2-2x-x+2); (6x^2+7x+2)=6(x^2-x+2); 6x^2+7x+2=6x^2-6x+12; 7x+6x=12-2; ; 13x=10; x=10/13; ; (xiii)16x^2-3=(2x+5)(5x-3); 16x^2-3=(10x^2-6x+25x-15); 16x^2-3=10x^2+19x-15); 16x^2-10x^2-3+15=19x; 6x^2+12-19x x^2+1/x^2=3; . ( x+1/x)(x-1/x)=3; ; ( x^2+1/x)( x^2-1/ x^2)=3; ( x^2+1/x^2)=3; ( x+1/x)(x-1/x)= ( x^2+1/x)(x^2-1/x)=3,; ( x^2+1)( x^2-1)=3; x^4-x^2+x^2-1=3; x^4=3+1=4, x^4=(1)^4; x=1 viii)x+1/x=1; squares on both; (x+1/x)^2=1^2; x^2+(1/x^2)+2.x.1/x=1; x^2+1/x^2=1; iv)x-3/x=x^2; (x-3/x)^2=( x^2)^2; ) ( x^2+3/x^2-2.( x)(1/x)= x^4; x^2+3/x^2-2= x^4 (xiv)( x+2)^3=x^3-4; ( x+2)^3=x^3+8+3(x)2(x+2)= x^3+8+6x( x+2)=x^3-4; 8+6x^2+12x=-4; 6x^2+12x+4=0; (xv)x(x+1)+8=( x+2)( x-2); x( x+1)+8=x^2+x+8; ( x+2)( x-2)=( x^2-2x+2x-4)=( x^2-4); x^2-4=x^2+x+8, x+8+4=x+12; x=-12 x= 3 is the correct answer x= 3 is the correct answer any equation have power 2 is called quadratic equation general quadratic equationax^2+bx+C=0x^2+2x+1=0x^2-6x-4=0 |
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