Example 8: In Fig. 6.38, the sides AB and AC ofAABC are produced to po

1.	Example 8: In Fig. 6.38, the sides AB and AC ofAABC are produced to points E and D respectivelyIf bisectors BO and CO of CBE and BCDrespectively meet at point O, then prove thatSolution : Ray BO is the bisector of 2 CBETherefore, < CBO- < CBE- (180-y)= 90°-- (1)Similarly, ray CO is the bisector of ACD.Fig. 6.38Therefore,
Answer» its a solved example .. so what is your query say?? I cant understand the solved eg. so for understanding you need a video session .. for this you can join this page and post your query you will get explanatory video this page https://www.facebook.com/Class-6-To-10-Preparation-Cbse-2250343781851299/ Pls specify the answer

Example 8: In Fig. 6.38, the sides AB and AC ofAABC are produced to points E and D respectivelyIf bisectors BO and CO of CBE and BCDrespectively meet at point O, then prove thatSolution : Ray BO is the bisector of 2 CBETherefore, < CBO- < CBE- (180-y)= 90°-- (1)Similarly, ray CO is the bisector of ACD.Fig. 6.38Therefore,

Answer»

its a solved example .. so what is your query say??

I cant understand the solved eg.

so for understanding you need a video session .. for this you can join this page and post your query you will get explanatory video this page https://www.facebook.com/Class-6-To-10-Preparation-Cbse-2250343781851299/

Pls specify the answer

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