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Example 27 Find the value of tan |
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Answer» tan(π/8)= tan(π/4–π/8) tan(π/8)=[1-tan(π\8)]/[1+tan(π/8]{I've skipped a step here} Now, you get a quadratic eqn. tan^2(π/8)+tan(π/8)-1=0 .°. tan(π/8)=(-2+2√2)/2{I’ve taken’ +’ because it's in the first quadrant} =-1+√2 =0.414 Like my answer if you find it useful! |
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