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Example 24 Solve 2 cos? x + 3 sin x = 0

Answer»

2cos^2x+3sinx=02(1-sin^2x)+3sinx=02-2sin^2x+3sinx=02sin^2x-3sinx-2=02sin^2x-4sinx+sinx-2=02sinx(sinx-2)+1(sinx-2)=0(sinx-2)(2sinx+1)=0either sinx-2=0, since=2or 2sinx+1=02sinx= -1sinx= -1/2



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