it's the right answer of this question

Let us consider that 3root2 is a rational number. It can be written in the form p/q (p and q are co primes)

p/q = 3root2

p/3q = root2

Now,

p/3q = integer/interger

= rational number

But, this contradicts the fact that root2 is irrational.

Therefore, our assumption that 3root2 is rational is WRONG.

Hence, 3root2 is an irrational number.

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sonali9898 ExpertIf possible let 3 root under 2 is rational.

Then there exists co primes a and b (b not equal to 0)

such that

3 root under 2 = a/b

= root under 2 = a/3b

since a and b are integers so a/3b is rational.

thus, root under 2 is also rational.

But , this contradicts the fact that root under 2 is irrational . so our assumption is incorrect.

Hence 3 root under 2 is irrational.

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it's the right answer of this question

it's the right answer of this question

1.141×33.423is correct answer