Example 10: In the following figurerectangle in which the segments AP

1.	Example 10: In the following figurerectangle in which the segments AP and AQ are drawnas shown. Find the length of (AP + AQ).ABCD is a30°30°60 cm
Answer» In right triangle APB30° + 90° + <PAB = 180°<PAB = 180° - 120° = 60° Then, cos 60° = B/H = AB/AP 1/2 = 60/APAP = 602 = 120 cm In right triangle AQDsin 30° = P/H = AD/AQ1/2 = 30/AQAQ = 302 = 60 cm Therefore, length of (AP + AQ) = 120 + 60= 180 cm

Example 10: In the following figurerectangle in which the segments AP and AQ are drawnas shown. Find the length of (AP + AQ).ABCD is a30°30°60 cm

Answer»

In right triangle APB30° + 90° + <PAB = 180°<PAB = 180° - 120° = 60°

Then, cos 60° = B/H = AB/AP 1/2 = 60/APAP = 60*2 = 120 cm

In right triangle AQDsin 30° = P/H = AD/AQ1/2 = 30/AQAQ = 30*2 = 60 cm

Therefore, length of (AP + AQ) = 120 + 60= 180 cm