1.

.Examine Whether (x-3) is a factor of x^3-4x^2+x+6.

Answer»

\huge\bf\purple{Polynomials}

FIRST we will FIND the the ZERO of x-3 that will be-

x - 3 = 0

x = 0 + 3

x = 3

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Now,

p(x) = x {}^{3} - 4x {}^{2} + x + 6

p(3) =(3)^{3} - 4(3) {}^{2} + (3) + 6

=>27 - 36 + 3 + 6

= > 0 \: ans

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\therefore x-3 is the FACTOR.


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