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Evalute using suitable identities (z+7)(z+6) |
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Answer» YE IK EXAMPLE h iske trah solve kro usse bhi Step-by-step explanation: 2a−7)(2a−7)=(2a−7) 2
using identity (a−b) 2 =a 2 −2ab+b 2
(2a−7) 2 =(2a) 2 −2×2a×7+7 2
(2a−7) 2 =4a 2 −28a+49 |
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