1.

Evalute using suitable identities (z+7)(z+6)​

Answer»

ANSWER:

YE IK EXAMPLE h iske trah solve kro usse bhi

Step-by-step explanation:

2a−7)(2a−7)=(2a−7)

2

using identity (a−b)

2

=a

2

−2ab+b

2

(2a−7)

2

=(2a)

2

−2×2a×7+7

2

(2a−7)

2

=4a

2

−28a+49



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