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Evaluate y2+y2+2+.. to infinity |
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Answer» expression under square root extends infinitely then expression in brackets would equal toxxitself so we can rewrite given expression asx=2+x−−−−−√x=2+x. Square both sidesx²=2+x-->after solving this equationx^2-x-2= 0x=2orx=−1 As given thatx>1then only one solution is valid:x=2 |
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