Evaluate: sin[π/3 - sin-1(-1/2)] – InterviewSolution

1.

Evaluate: sin[π/3 - sin-1(-1/2)]

Answer»

sin[π/3 - sin^-1(-1/2)] = sin[π/3 - (- π/6)]

= sin[π/3 + π/6] = sinπ/2 = 1

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