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Evaluate `S=sum_(n=0)^n(2^n)/((a^(2^n)+1)` (where `a>1)`. |
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Answer» `S=sum_(n=0)^(oo)(2^(n))/(a^(2n)+1)(agt1)` `S_(n)=sum_(n=0)^(n)(2^(n))/(a^(2n)+1)` `=(1)/(a+1)+(2)/(a^(2)+1)+(4)/(a^(4)+1)+(8)/(a^(8)+1)+"........"+(2^(n))/(a^(2^n)+1)` `=(1)/(1+a)+(2)/(1+a^(2))+(4)/(1+a^(4))+(8)/(1+a^(8))+"........"+(2^(n))/(1+a^(2^n))` `=(-(1)/(1-a)+(1)/(1-a))(1)/(1+a)+(2)/(1+a^(2))+(4)/(1+a^(4))+(8)/(1+a^(8))+"........"+(2^(n))/(1+a^(2^n))` `=(1)/(a-1)+((1)/(1-a)+(1)/(1+a))+(2)/(1+a^(2))+(4)/(1+a^(4))+"........"+(2^(n))/(1+a^(2^n))` `=(1)/(a-1)+((2)/(1-a^(2))+(2)/(1+a^(2)))+(4)/(1+a^(4))+"........"+(2^(n))/(1+a^(2^n))` `" " vdots " "vdots " " vdots " "` `S_(n)=(1)/(a-1)+(2^(n+1))/(1-a^(2^n+1))` `S=lim_(n to oo)S_(n)=lim_(n to oo)((1)/(a-1)+(2^(n+1))/(1-a^(2^n+1)))` `=lim_(n to oo)((1)/(a-1)+((2^(n+1))/(a^(2^n+1)))/((1)/(a^(2^n+1))-1))=(1)/(a-1)+(0)/(0-1)=(1)/(a-1)`. |
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