1.

Evaluate:\(\frac{tan\, 10°}{cot\, 80°}\)

Answer»

We have, 

\(\frac{tan 10°}{cot 80°}\)

= \(\frac{tan (90° – \,10°) }{cot 80°}\)

= \(\frac{cot 80°}{cos 80° }\)

= 1 [∵ tan (90 – θ) = cot θ]



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