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Evaluate:\(\frac{tan\, 10°}{cot\, 80°}\) |
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Answer» We have, \(\frac{tan 10°}{cot 80°}\) = \(\frac{tan (90° – \,10°) }{cot 80°}\) = \(\frac{cot 80°}{cos 80° }\) = 1 [∵ tan (90 – θ) = cot θ] |
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