Evaluate:\frac{\cot 54^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ} – InterviewSolution

1.	Evaluate:\frac{\cot 54^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ}}{\cot 70^{\circ}}-2
Answer» cot (90-54) = tan 36tan(90-20)= cot70so tan 36/tan36+tan20/cot20-22-2=0

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