Evaluate :∫dx/1+x2 for x→[1,√3]

1.	Evaluate :∫dx/1+x2 for x→[1,√3]
Answer» I = ∫ (1+logx)²/x dx Let 1 + log x = z 1/x dx = dz => I = ∫z²dz = Z³ / 3 +C =1/3(1 + logx)³+ c

Answer»

I = ∫ (1+logx)²/x dx

Let 1 + log x = z

1/x dx = dz => I = ∫z²dz

= Z³ / 3 +C =1/3(1 + logx)³+ c

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Evaluate :∫dx/1+x2 for x→[1,√3]

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