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Evaluate∛64 |
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Answer» The prime factors of 64 = 2 × 2 × 2 × 2 × 2 × 2 Now by grouping into three we get, (2 × 2 × 2) × (2 × 2 × 2) ∴ \(\sqrt[3]{((2)^3 × (2)^3)}\) = (2 × 2) = 4 |
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