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Evaluate: (3²+1)/(3²-1)+(5²+1)/(5²-1)+.... +(99²+1)/(99²-1) |
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Answer» Answer: Every term of SERIES simplifies to and x = 3, 5, 7, ...., 99 (odd NUMBERS). Now WRITE first three or four TERMS of series, each in new line, by putting x = 3, 5, 7, 9. You can see that some terms will be cancelled out. The final sum is given by , it simplifies to
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