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Evaluate (2x^2+3x-7)*(3x^2-5x+4) |
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Answer» <P>Answer: Step-by-step explanation: (2x²+3x−7)(3x²−5x+4)→ (2x²)(3x²)+(2x²)(−5x)+(2x²)(4)+(3x)(3x²)+(3x)(−5x)+(3x)(4)+(−7)(3x²)+(−7)(−5x)+(−7)(4) → 6x⁴−10x³+8x²+9x³−15x²+12x−21x²+35x−28 → 6x⁴−x³−28x²+47x−28 You need to know that :-
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