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Evaluate∛-216 |
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Answer» The prime factors of 216 = 2 × 2 × 2 × 3 × 3 × 3 Now by grouping into three we get, (2 × 2 × 2) × (3 × 3 × 3) ∴ \(\sqrt[3]{ – ((2)^3 × (3)^3)}\) = – (2 × 3) = -6 |
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