Evaluate∛1728 – InterviewSolution

1.

Evaluate∛1728

Answer»

The prime factors of 1728 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3

Now by grouping into three we get, (2 × 2 × 2) × (2 × 2 × 2) × (3 × 3 × 3)

∴ \(\sqrt[3]{((2)^3 × (2)^3× (3)^3) }\)

= (2 × 2 × 3)

= 12

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