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Evaluate :- 1+i2+i4+i6+.................+i2n |
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Answer» if n is even answer is zeroif n is odd answer is one if n is odd the answer will be zeroif n is even all cancel and answer is 1 We know i\u200b\u200b\u200b\u200b\u200b\u200b2= -1\xa0And\xa0{tex}i^4=(i^2)^2=(-1)^2= 1{/tex}So all the terms having i will be cancelled out. We ll get answer as 1\xa0 |
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