1.

Europium and Ytterbium behave as good reducing agents in +2 oxidation state explain.

Answer»
  • The most stable oxidation state of lanthanoids is + 3.
  • Hence, Eu2+ and Yb2+ tend to get + 3 oxidation states by losing one electron.
  • Since they get oxidised, they are good reducing agents in + 2 oxidation state.


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