1.

Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :C2H4(g)+HCl(g)→C2H5Cl(g) ΔH=−72.3kJ. What is the value of ΔE (in KJ), if 70g of ethylene and 73g of HCl are allowed to react at 300K?

Answer»

Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :


C2H4(g)+HCl(g)C2H5Cl(g) ΔH=72.3kJ. What is the value of ΔE (in KJ), if 70g of ethylene and 73g of HCl are allowed to react at 300K?





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