Ethyl chloride (C2H5Cl) is prepared by reaction of ethylene with hydro – InterviewSolution

1.	Ethyl chloride (C2H5Cl) is prepared by reaction of ethylene with hydrogen chloride: C2H4(g)+HCl(g)→C2H5Cl(g)△H=−72.3 kJ/mol What is the value of △U (in kJ), if 98 g of ethylene and 109.5 g of HCl are allowed to react at 300 K?
Answer» Ethyl chloride $(C_{2} H_{5} C l)$ is prepared by reaction of ethylene with hydrogen chloride: $C_{2} H_{4} (g) + H C l (g) \to C_{2} H_{5} C l (g) △ H = - 72.3 k J / m o l$ What is the value of $△ U$ (in $k J$ ), if $98 g$ of ethylene and 109.5 g of $H C l$ are allowed to react at $300 K$ ?

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