1.

Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride : C2H4(g)+HCl(g)→C2H5Cl(g) ΔH=−72.3kJ. What is the value of △E (in KJ), if 70g of ethylene and 73g of HCL are allowed to react at 300K.

Answer»

Ethyl chloride (C2H5Cl), is prepared by reaction of ethylene with hydrogen chloride :

C2H4(g)+HCl(g)C2H5Cl(g) ΔH=72.3kJ. What is the value of E (in KJ), if 70g of ethylene and 73g of HCL are allowed to react at 300K.




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