1.

etermine tha value of "K for which Kr+3y=k-312x+ky=krepresent coincident lines

Answer»

If lines kx + 3y = k - 3 and12x + ky = k are coincident lines

K/12 = 3/k = k-3/k

Then,K/12 = 3/kk^2 = 36k = 6, - 6

Therefore value of k = 6, - 6



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